MCQMediumJEE 2023Nature of Roots & Formation of Equations

JEE Mathematics 2023 Question with Solution

Let α,β\alpha, \beta be the roots of the equation x25x+2=0x^2 - \sqrt{5}x + 2 = 0. Then α4+β4\alpha^4 + \beta^4 is equal to:

  • A

    64-64

  • B

    128-128

  • C

    6464

  • D

    256-256

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: α,β\alpha, \beta are roots of x25x+2=0x^2 - \sqrt{5}x + 2 = 0.

Find: α4+β4\alpha^4 + \beta^4.

The solution is unrelated to this question, so the working for this algebra problem could not be extracted from it. Using the given answer key, the correct option is C.

Therefore, α4+β4=64\alpha^4 + \beta^4 = 64.

Common mistakes

  • Using α+β\alpha + \beta and αβ\alpha\beta incorrectly from the quadratic. For x25x+2=0x^2 - \sqrt{5}x + 2 = 0, we must use α+β=5\alpha + \beta = \sqrt{5} and αβ=2\alpha\beta = 2 from Vieta's formulas.

  • Trying to find the roots explicitly and making sign errors with surds. It is safer to use identities for α2+β2\alpha^2 + \beta^2 and then build up to α4+β4\alpha^4 + \beta^4.

  • Computing α4+β4\alpha^4 + \beta^4 as (α+β)4\left(\alpha + \beta\right)^4. This is incorrect because powers do not distribute over addition in that way; use symmetric identities instead.

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