Among (S1) n 1n ( 2 + 4 + 6 + + 2n) = 1 (S2) n 116 ( 1^15 + 2^15 + 3^15 + + n^15) = 116

Among (S1) n 1n ( 2 + 4 + 6 + + 2n) = 1 (S2) n 116 ( 1^15 + 2^15… - Solution | JEE Mathematics

MCQMediumJEE 2023Limits

Among

(S1) $\lim_{n \to \infty} \frac{1}{n} \left( 2 + 4 + 6 + \dots + 2n \right) = 1$

(S2) $\lim_{n \to \infty} \frac{1}{16} \left( 1^{15} + 2^{15} + 3^{15} + \dots + n^{15} \right) = \frac{1}{16}$

Correct answer:D

Standard Method

Given: Two statements (S1) and (S2) are to be checked.

Find: Which option correctly identifies the true statement(s).

The solution explicitly states: The Correct Option is D.

Therefore, the correct option is D, that is, Only (S2) is true.

No step-by-step working was present in the solution, so the intermediate justification could not be extracted.

Treating the answer key as final even when the solution states a different option. The Use the solution conclusion first.
Assuming both statements must be evaluated from external knowledge when the solution contains only the final option. In this extraction task, do not invent missing derivation steps; report the stated conclusion instead.

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