NVAMediumJEE Main 2023 · 12 April, Shift 1Definite Integrals

Mathematics Question from JEE Main 2023 · 12 April, Shift 1

If 0.150.15100x21dx=k3000\int_{-0.15}^{0.15} \left| 100x^2 - 1 \right| \, dx = \frac{k}{3000}, then kk is equal to:

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