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MCQMediumJEE Main 2023 · 12 April, Shift 1Argand Plane & Geometry

Mathematics Question from JEE Main 2023 · 12 April, Shift 1

Let CC be the circle in the complex plane with centre z0=12(1+3i)z_0 = \frac{1}{2}(1 + 3i) and radius r=1r = 1. Let z1=1+iz_1 = 1 + i and the complex number z2z_2 be outside the circle CC such that ∣z1−z0∣ ∣z2−z0∣=1|z_1 - z_0|\,|z_2 - z_0| = 1. If z0,z1z_0, z_1 and z2z_2 are collinear, then the smaller value of ∣z2∣2|z_2|^2 is equal to:

  • A

    132\frac{13}{2}

  • B

    52\frac{5}{2}

  • C

    32\frac{3}{2}

  • D

    72\frac{7}{2}

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