MCQMediumJEE Main 2023 · 12 April, Shift 1Quadratic Equations in Complex Numbers

Mathematics Question from JEE Main 2023 · 12 April, Shift 1

Let α,β\alpha, \beta be the roots of the quadratic equation x2+6x+3=0x^2 + \sqrt{6}x + 3 = 0. Then, α23+β23+α14+β14α15+β15+α10+β10\frac{\alpha^{23} + \beta^{23} + \alpha^{14} + \beta^{14}}{\alpha^{15} + \beta^{15} + \alpha^{10} + \beta^{10}} is equal to:

  • A

    729729

  • B

    7272

  • C

    8181

  • D

    99

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