NVAEasyJEE Main 2023 · 11 April, Shift 2Surface Tension & Capillarity

Physics Question from JEE Main 2023 · 11 April, Shift 2

The surface tension of soap solution is 3.5×102N m13.5 \times 10^{-2} \, \text{N m}^{-1}. The amount of work done required to increase the radius of soap bubble from 10cm10 \, \text{cm} to 20cm20 \, \text{cm} is _____ ×104J\times 10^{-4} \, \text{J}. (take π=22/7\pi = 22/7)

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