In the Provided that circuit, C1 = 2 F, C2 = 0.2 F, C3 = 2 F, C4 = 4 F, C5 = 2 F, C6 = 2 F. The charge stored on capacit

Question

In the Provided that circuit, C1 = 2 F, C2 = 0.2 F, C3 = 2 F, C4 = 4 F, C5 = 2 F, C6 = 2 F. The charge stored on capacitor C4 is C.

Accepted Answer

Given: The solution states that the total equivalent capacitance is $0.5 \, \mu\text{F}$ and the applied voltage is $10 \, \text{V}$ .

Find: The charge stored on capacitor $C_4$ .

Using the equivalent capacitance, the total charge in the circuit is

Q = C_{\text{eq}} \cdot V

Substituting the values given in the solution:

Q = 0.5 \times 10 = 5 \, \mu\text{C}

Now use the charge division relation quoted in the solution for the relevant branch:

Q' = Q \cdot \frac{C_2}{C_2 + C_6}

The solution substitutes:

Q' = 5 \cdot \frac{0.8}{0.8 + 0.2}

So,

Q' = 5 \cdot 0.8 = 4 \, \mu\text{C}

Therefore, the charge stored on capacitor $C_4$ is $4 \, \mu\text{C}$ . Hence the numerical answer is 4.

Note: The extracted solution contains an internal inconsistency because the question states $C_2 = 0.2 \, \mu\text{F}$ , while the working uses $0.8 \, \mu\text{F}$ in the charge division step. However, the solution concludes the final value as $4 \, \mu\text{C}$ , and that is taken as the answer.

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