MCQEasyJEE 2023Molecular Speeds (rms, Average, Most Probable)

JEE Physics 2023 Question with Solution

The root mean square speed of molecules of nitrogen gas at 27C27^\circ \text{C} is approximately : (Provided that mass of a nitrogen molecule =4.6×1026kg= 4.6 \times 10^{-26} \, \text{kg} and take Boltzmann constant kB=1.4×1023JK1k_B = 1.4 \times 10^{-23} \text{J} \text{K}^{-1})

  • A

    1260m/s1260 \, \text{m/s}

  • B

    91m/s91 \, \text{m/s}

  • C

    523m/s523 \, \text{m/s}

  • D

    27.4m/s27.4 \, \text{m/s}

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: Temperature T=27C=300KT = 27^\circ \text{C} = 300 \, \text{K}, mass of one nitrogen molecule m=4.6×1026kgm = 4.6 \times 10^{-26} \, \text{kg}, and Boltzmann constant kB=1.4×1023J/Kk_B = 1.4 \times 10^{-23} \, \text{J/K}.

Find: The root mean square speed VrmsV_{\text{rms}} of nitrogen molecules.

For an ideal gas molecule,

Vrms=3kBTmV_{\text{rms}} = \sqrt{\frac{3k_B T}{m}}

Substituting the given values,

Vrms=3×1.4×1023×3004.6×1026V_{\text{rms}} = \sqrt{\frac{3 \times 1.4 \times 10^{-23} \times 300}{4.6 \times 10^{-26}}}

Simplifying the numerator,

3×1.4×300=1260×1023=1.26×10203 \times 1.4 \times 300 = 1260 \times 10^{-23} = 1.26 \times 10^{-20}

So,

1.26×10204.6×1026=2.73×105\frac{1.26 \times 10^{-20}}{4.6 \times 10^{-26}} = 2.73 \times 10^5

Taking the square root,

Vrms=2.73×105523m/sV_{\text{rms}} = \sqrt{2.73 \times 10^5} \approx 523 \, \text{m/s}

Therefore, the root mean square speed of nitrogen molecules is approximately 523m/s523 \, \text{m/s}. The solution working gives the correct option as C, even though the solution incorrectly states D.

Common mistakes

  • Using temperature directly as 2727 instead of converting it to absolute temperature is incorrect because kinetic theory formulas require Kelvin. Convert 27C27^\circ \text{C} to 300K300 \, \text{K} before substitution.

  • Using the wrong speed formula, such as average speed or most probable speed, gives a different numerical value. Here the required formula is specifically Vrms=3kBTmV_{\text{rms}} = \sqrt{\frac{3k_B T}{m}}.

  • Mishandling powers of 1010 during simplification can produce answers like 12601260 or 27.427.4. First combine the scientific notation carefully, then take the square root only at the final step.

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