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MCQEasyJEE Main 2023 · 11 April, Shift 2Relative Motion

Physics Question from JEE Main 2023 · 11 April, Shift 2

When vector A⃗=2i^+3j^+2k^\vec{A} = 2\hat{i} + 3\hat{j} + 2\hat{k} is subtracted from vector B⃗\vec{B}, it gives a vector equal to 2j^2\hat{j}. Then the magnitude of vector B^\hat{B} will be:

  • A

    33

  • B

    5\sqrt{5}

  • C

    33\sqrt{33}

  • D

    6\sqrt{6}

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