NVAMediumJEE Main 2023 · 11 April, Shift 2Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2023 · 11 April, Shift 2

Let the tangent to the parabola y2=12xy^2 = 12x at the point (3,α)(3, \alpha) be perpendicular to the line 2x+2y=32x + 2y = 3. Then the square of the distance of the point (6,4)(6, -4) from the normal to the hyperbola α2x29y2=9α2\alpha^2 x^2 - 9y^2 = 9\alpha^2 at its point (α1,α+2)(\alpha - 1, \alpha + 2) is equal to _____.

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Conic Sections (Parabola, Ellipse, Hyperbola) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions