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MCQMediumJEE Main 2023 · 11 April, Shift 2Determinants Basics

Mathematics Question from JEE Main 2023 · 11 April, Shift 2

If:

∣x+1xxxx+λxxxx+λ2∣=98(103x+81)\begin{vmatrix} x + 1 & x & x \\ x & x + \lambda & x \\ x & x & x + \lambda^2 \end{vmatrix} = \frac{9}{8}(103x + 81)

then λ,λ3\lambda, \frac{\lambda}{3} are the roots of the equation:

  • A

    4x2−24x−27=04x^2 - 24x - 27 = 0

  • B

    4x2+24x+27=04x^2 + 24x + 27 = 0

  • C

    4x2−24x+27=04x^2 - 24x + 27 = 0

  • D

    4x2+24x−27=04x^2 + 24x - 27 = 0

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