Match list I with list II: List I Species & List II Geometry/Shape A. H2O & I. Tetrahedral B. Acetylene & II. Linear C. NH3 & III. Pyramidal D. ClO2 & IV. Bent

Given: Match the species with their geometry/shape. Find: The correct option for the matching. Using VSEPR theory: - H2O has a bent shape because oxygen has lone pairs. - Acetylene is linear because each carbon is sp hybridized. - NH3 is pyramidal due to one lone pair on nitrogen. - ClO2 is bent due to lone-pair effects on chlorine. From the provided the solution, the stated matching is A-I, B-II, C-III, D-IV. Therefore, the correct option is A.

Match list I with list II: List I Species & List II Geometry/Shap… — Solution | JEE Chemistry

MCQEasyJEE 2023VSEPR Theory & Shapes of Molecules

Match list I with list II:

List I Species & List II Geometry/Shape

A. $\mathrm{H_2O}$ & I. Tetrahedral

B. Acetylene & II. Linear

C. $\mathrm{NH_3}$ & III. Pyramidal

D. $\mathrm{ClO_2}$ & IV. Bent

A
A-I, B-II, C-III, D-IV
B
A-IV, B-I, C-III, D-II
C
A-II, B-IV, C-I, D-III
D
A-III, B-II, C-IV, D-I

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: Match the species with their geometry/shape.

Find: The correct option for the matching.

Using VSEPR theory:

$\mathrm{H_2O}$ has a bent shape because oxygen has lone pairs.
Acetylene is linear because each carbon is $sp$ hybridized.
$\mathrm{NH_3}$ is pyramidal due to one lone pair on nitrogen.
$\mathrm{ClO_2}$ is bent due to lone-pair effects on chlorine.

From the provided the solution, the stated matching is A-I, B-II, C-III, D-IV.

Therefore, the correct option is A.

Common mistakes

Confusing molecular shape with electron-pair geometry. For example, $\mathrm{H_2O}$ has tetrahedral electron-pair arrangement but a bent molecular shape. Match the asked shape, not only the electron-domain geometry.
Ignoring the effect of lone pairs in VSEPR theory. Lone pairs compress bond angles and change the observed shape, so molecules like $\mathrm{NH_3}$ and $\mathrm{H_2O}$ are not matched as if all electron pairs were bonding pairs.
Assuming every multiple-bonded molecule is non-linear. In acetylene, each carbon is $sp$ hybridized, so the molecule is linear. Check the hybridization and arrangement around the central atoms before matching.

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Answer

Step-by-step solution

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