When a solution of mixture having two inorganic salts was treated with freshly prepared ferrous sulphate in acidic medium, a dark brown ferric ion was formed when treated with ferric chloride. It gave deep red colour which disappeared on boiling and a brown red ppt was formed. The mixture contains:
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Correct answer:C
Standard Method
Given: The mixture gives a deep red colour with ferric chloride, which disappears on boiling, and a brown red precipitate is formed.
Find: The ions or salts present in the mixture.
The solution description identifies the characteristic test of acetate ion with ferric chloride. Acetate gives a deep red coloration due to formation of ferric acetate complex, and on boiling this colour disappears with formation of a brown red precipitate.
Therefore, the mixture contains and .
The correct option is C.
Confusing the deep red colour test with nitrate analysis is incorrect because nitrate is commonly identified by the brown ring test with freshly prepared ferrous sulphate in acidic medium. Here, the decisive observation is the ferric chloride test and the disappearance of red colour on boiling, which points to acetate.
Selecting sulphate is incorrect because sulphate does not give a deep red colour with ferric chloride. Focus on characteristic confirmatory colour changes rather than matching only one ion from the statement.
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