JEE Physics 2023 Question with Solution

Given: The current through the $3 \, \Omega$ resistor is stated to be $\frac{x}{3} \, A$.

Find: The value of $x$.

From the solution, the conclusion explicitly states: "The correct option is (C): 0.8A."

Therefore, the current through the $3 \, \Omega$ resistor is $0.8 \, A$.

So,

$$\frac{x}{3} = 0.8$$

Hence,

$$x = 3 \times 0.8 = 2.4$$

This does not match any listed option value directly. However, the solution explicitly marks option C as correct. Therefore, based on the solution authority, the correct option is C.

There is a discrepancy between the numerical conclusion $x = 2.4$ and the listed options $1, 2, 3, 4$. The source solution identifies C as the answer.