Let be a rectangle given by the line . Let and with and , be such that the line segment divides the area of the rectangle in the ratio . Then, the midpoint of lies on:
- A
Straight line
- B
Parabola
- C
Circle
- D
Hyperbola
Let be a rectangle given by the line . Let and with and , be such that the line segment divides the area of the rectangle in the ratio . Then, the midpoint of lies on:
Straight line
Parabola
Circle
Hyperbola
Correct answer:B
Standard Method
Given: The rectangle is shown with intercepts leading to points and , and the line segment divides the rectangle in the ratio .
Find: The locus of the midpoint of .

From the solution,
Also,
So,
If the midpoint is , then its coordinates satisfy
Hence, the midpoint lies on a hyperbola.
Therefore, the correct curve is Hyperbola. The solution states the correct option is B, although the listed option text shows Hyperbola as option D. the answer is recorded as B.
Detailed Working from Extracted Solution
Given: and , and the midpoint of is
Find: The nature of the locus of .
The extracted solution states that the midpoint has coordinates
and concludes that this locus is a hyperbola.
Using the area relation written in the extracted solution, the product of the midpoint coordinates becomes constant, which is of the form
for some constant . Such an equation represents a hyperbola.
Therefore, the midpoint of lies on a hyperbola.
Using the option list alone and ignoring the worked solution can be misleading here, because the solution says option B while the listed text places Hyperbola at option D. Always compare the final curve obtained from the working with the option text.
Treating the locus of the midpoint as a straight line is incorrect. The solution gives a relation of the form or , which is a product relation, not a linear one.
Confusing the coordinates of endpoints with the midpoint is a common error. If and , then the midpoint is , not . Use the midpoint formula carefully.
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