MCQEasyJEE 2023Characteristics of EM Waves

JEE Physics 2023 Question with Solution

The amplitude of magnetic field in an electromagnetic wave propagating along yy-axis is 6.0×107T6.0 \times 10^{-7} \, T. The maximum value of electric field in the electromagnetic wave is:

  • A

    2×1015Vm12 \times 10^{15} \, Vm^{-1}

  • B

    2×1014Vm12 \times 10^{14} \, Vm^{-1}

  • C

    6.0×107Vm16.0 \times 10^{-7} \, Vm^{-1}

  • D

    180Vm1180 \, Vm^{-1}

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Amplitude of magnetic field is B0=6.0×107TB_0 = 6.0 \times 10^{-7} \, \text{T}.

Find: Maximum value of electric field E0E_0 in the electromagnetic wave.

For an electromagnetic wave,

E0=cB0E_0 = cB_0

where c=3×108m/sc = 3 \times 10^8 \, \text{m/s}.

Substituting the given value,

E0=(3×108)(6.0×107)E_0 = (3 \times 10^8)(6.0 \times 10^{-7}) E0=18×101=180Vm1E_0 = 18 \times 10^1 = 180 \, \text{Vm}^{-1}

Therefore, the maximum value of the electric field is 180Vm1180 \, \text{Vm}^{-1}. The listed solution says option B, but its own calculation gives 180Vm1180 \, \text{Vm}^{-1}, which matches option D.

Common mistakes

  • Using the inverse relation between E0E_0 and B0B_0. This is wrong because in an electromagnetic wave the correct relation is E0=cB0E_0 = cB_0, not E0=B0cE_0 = \frac{B_0}{c}. Always multiply B0B_0 by the speed of light.

  • Making an error in powers of ten while evaluating (3×108)(6.0×107)(3 \times 10^8)(6.0 \times 10^{-7}). This is wrong because 108×107=10110^8 \times 10^{-7} = 10^1. Combine coefficients and exponents separately before simplifying.

  • Choosing the option from the solution without checking the working. This is wrong because the header says B but the calculation clearly gives 180Vm1180 \, \text{Vm}^{-1}. Trust the worked result when there is a mismatch.

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