MCQEasyJEE Main 2023 · 10 April, Shift 2Satellites & Orbital Velocity

Physics Question from JEE Main 2023 · 10 April, Shift 2

The time period of a satellite, revolving above Earth's surface at a height equal to RR will be (Given g=π2m/s2,R=g = \pi^2 \, \text{m/s}^2, R = radius of earth ):

  • A

    32R\sqrt{32R}

  • B

    4R\sqrt{4R}

  • C

    2R\sqrt{2R}

  • D

    8R\sqrt{8R}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Satellites & Orbital Velocity questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions