MCQEasyJEE 2023Acceleration due to Gravity

JEE Physics 2023 Question with Solution

Physics Section-A

Given below are two statements:

Statement I: Rotation of the earth shows effect on the value of acceleration due to gravity (gg)

Statement II: The effect of rotation of the earth on the value of 'gg' at the equator is minimum and that at the pole is maximum.

In the light of the above statements, choose the correct answer from the options given below.

  • A

    Both Statement I and Statement II are true

  • B

    Both Statement I and Statement II are false

  • C

    Statement I is false but statement II is true

  • D

    Statement I is true but statement II is false

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: Two statements about the effect of Earth's rotation on acceleration due to gravity.

Find: Which statement is true.

The effective acceleration due to gravity due to Earth's rotation is

geff=gω2Rcos2θg_{\text{eff}} = g - \omega^2 R \cos^2 \theta

where θ\theta is the angle made with the equator.

At the poles, θ=90\theta = 90^\circ, so

cos90=0\cos 90^\circ = 0

and hence there is no change in gravity at the poles.

At the equator, θ=0\theta = 0^\circ, so the reduction is maximum:

geff=gω2Rg_{\text{eff}} = g - \omega^2 R

Thus, rotation of the Earth does affect the value of gg, so Statement I is true. Also, the effect is maximum at the equator and zero at the poles, so Statement II is false.

However, the provided solution explicitly concludes: The Correct Option is B.

Therefore, the correct option according to the solution is B.

Statement Analysis

Given: Statement I says Earth's rotation affects gg. Statement II says the effect is minimum at the equator and maximum at the pole.

Find: The correct option.

Earth's rotation produces a centrifugal effect, which reduces the effective value of gravity.

Using

geff=gω2Rcos2θg_{\text{eff}} = g - \omega^2 R \cos^2 \theta

we see that the reduction depends on cos2θ\cos^2 \theta.

  • At the equator, θ=0\theta = 0^\circ, so cos20=1\cos^2 0^\circ = 1. The reduction is maximum.
  • At the poles, θ=90\theta = 90^\circ, so cos290=0\cos^2 90^\circ = 0. The reduction is zero.

So Statement I is true and Statement II is false. This corresponds to option D in the listed choices.

But the solution labels the correct option as B, which is inconsistent with its own explanation and with the listed options. Following the instruction that solution is the primary source, the recorded answer is B while noting this discrepancy.

Common mistakes

  • Assuming the rotational effect on gg is maximum at the poles is incorrect because the centrifugal contribution is zero there. Instead, check the angular dependence in geffg_{\text{eff}} before concluding.

  • Confusing true physical reasoning with the option letter shown on the page can lead to error. Here, the explanation supports Statement I true and Statement II false, but the page marks option B, so the provided content is inconsistent.

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