In the figure, θ₁ + θ₂ = π/2 and √3 BE = 4 AB. If the area of △ C… | JEE Main 2023 Mathematics PYQ

NVAHardJEE Main 2023 · 10 April, Shift 2Properties of Triangles

In the figure, $\theta_1 + \theta_2 = \frac{\pi}{2}$ and $\sqrt{3} \, BE = 4 \, AB$ . If the area of $\triangle CAB$ is $2\sqrt{3} - 3$ square units, when $\frac{\theta_2}{\theta_1}$ is the largest, then the perimeter (in units) of $\triangle CED$ is equal to:

Geometric figure with points A, B, C, D, E; right angle at A between AC and AB, right angle at B with vertical BE, right angle at D on CD and DE, with angles theta_1 at B and theta_2 at C.

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