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MCQMediumJEE Main 2023 · 10 April, Shift 2Equation of Plane

Mathematics Question from JEE Main 2023 · 10 April, Shift 2

Let the line x1=6−y2=z+85\frac{x}{1} = \frac{6 - y}{2} = \frac{z + 8}{5} intersect the lines x−54=y−73=z+21\frac{x - 5}{4} = \frac{y - 7}{3} = \frac{z + 2}{1} and x+36=3−y3=z−61\frac{x + 3}{6} = \frac{3 - y}{3} = \frac{z - 6}{1} at the points A and B respectively. Then the distance of the mid-point of the line segment AB from the plane 2x−2y+z=142x - 2y + z = 14 is:

  • A

    33

  • B

    103\frac{10}{3}

  • C

    44

  • D

    113\frac{11}{3}

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