MCQMediumJEE Main 2023 · 10 April, Shift 2Definite Integrals

Mathematics Question from JEE Main 2023 · 10 April, Shift 2

Let ff be a continuous function satisfying 0t2(f(x)+x2)dx=43t3\int_0^{t^2} \left( f(x) + x^2 \right) \, dx = \frac{4}{3} t^3, t>0\forall t > 0. Then f(π24)f \left( \frac{\pi^2}{4} \right) is equal to:

  • A

    π2(1+π216)-\pi^2 \left( 1 + \frac{\pi^2}{16} \right)

  • B

    π(1π316)\pi \left( 1 - \frac{\pi^3}{16} \right)

  • C

    π(1+π316)-\pi \left( 1 + \frac{\pi^3}{16} \right)

  • D

    π2(1π316)\pi^2 \left( 1 - \frac{\pi^3}{16} \right)

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