A particle executes S.H.M. of amplitude A along the x-axis. At t… | JEE Main 2023 Physics PYQ

MCQEasyJEE Main 2023 · 10 April, Shift 1Simple Harmonic Motion (SHM)

A particle executes S.H.M. of amplitude $A$ along the x-axis. At $t = 0$ , the position of the particle is $x = \frac{A}{2}$ , and it moves along the positive x-axis. The displacement of the particle in time $t$ is given as $x = A \sin(\omega t + \delta)$ . The value of $\delta$ will be:

A
$\frac{\pi}{4}$
B
$\frac{\pi}{2}$
C
$\frac{\pi}{3}$
D
$\frac{\pi}{6}$

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