MCQEasyJEE 2023Group 17 Elements

JEE Chemistry 2023 Question with Solution

Which halogen is known to cause the reaction given below: 2Cu2++4XCu2X2(s)+X22Cu^{2+} + 4X^- \to Cu_2X_2(s) + X_2

  • A

    All halogens

  • B

    Only chlorine

  • C

    Only bromine

  • D

    Only iodine

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The reaction is

2Cu2++4ICu2I2+I22Cu^{2+} + 4I^- \to Cu_2I_2 + I_2

Find: Which halogen can cause the given reaction.

The reaction involves reduction of Cu2+Cu^{2+} to Cu+Cu^+ and simultaneous oxidation of II^- to I2I_2, forming precipitated Cu2I2Cu_2I_2.

Among the halides, only iodide ions have sufficient reducing strength to reduce Cu2+Cu^{2+} to Cu+Cu^+ in this way:

2Cu2++4ICu2I2(s)+I22Cu^{2+} + 4I^- \to Cu_2I_2(s) + I_2

Therefore, the halogen corresponding to this reaction is iodine. The correct option is D.

Common mistakes

  • Assuming all halide ions behave identically with Cu2+Cu^{2+} is incorrect because their reducing strengths differ. Check which halide can actually reduce Cu2+Cu^{2+} to Cu+Cu^+.

  • Confusing the halogen X2X_2 with the halide ion XX^- leads to wrong reasoning. The reacting species is the halide ion, which gets oxidized to the halogen.

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