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MCQEasyJEE 2023Salt Analysis (Cations & Anions)

JEE Chemistry 2023 Question with Solution

Match List I with List II:

A matching table with List I species A. F⁻, B. SO₄²⁻, C. NO₃, D. Zn and List II maximum allowed concentration in ppm in drinking water: I. less than 50 ppm, II. less than 5 ppm, III. less than 2 ppm, IV. less than 500 ppm.
  • A

    A-III, B-II, C-I, D-IV

  • B

    A-II, B-I, C-III, D-IV

  • C

    A-IV, B-III, C-II, D-I

  • D

    A-I, B-II, C-III, D-IV

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: A matching question between species in drinking water and their maximum allowed concentrations in ppm.

Find: The correct correspondence between List I and List II.

From the given data in the solution:

  • F−\mathrm{F^-} matches <50 ppm< 50 \, \text{ppm}
  • SO42−\mathrm{SO_4^{2-}} matches <5 ppm< 5 \, \text{ppm}
  • NO3\mathrm{NO_3} matches <2 ppm< 2 \, \text{ppm}
  • Zn matches <500 ppm< 500 \, \text{ppm}

Therefore, the correct matching is:

A−I,  B−II,  C−III,  D−IVA-I,\; B-II,\; C-III,\; D-IV

Hence, the correct option is D.

Common mistakes

  • Confusing SO42−\mathrm{SO_4^{2-}} with NO3−\mathrm{NO_3^-} limits leads to an incorrect match. Read each species carefully and match it with the concentration stated in the table.

  • Ignoring the Roman numerals in List II and directly comparing only numerical values can cause mis-ordering. First identify I, II, III, IV, then map each species step by step.

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