Let denote the greatest integer . The is equal to:
JEE Mathematics 2023 Question with Solution
Answer
Correct answer:14
Step-by-step solution
Standard Method
Given: denotes the greatest integer function, and we need to evaluate
Find: The numerical value of the integral.
From the solution, first split the integral into two parts:
Step 1: Evaluate the part involving . On the interval , the solution states:
- from to , ,
- from to , .
Hence,
Evaluating,
Step 2: Evaluate the part involving . The solution uses the substitution and writes:
If this integral is denoted by , then the solution writes:
So it simplifies to
Then the solution concludes:
Step 3: Combine the results exactly as shown in the solution:
Therefore, the value of the integral is .
Piecewise Interval Insight
Given: The integral contains greatest integer functions of and over . Find: The required numerical value.
The key idea stated in the hint is to split the interval into subintervals where the floor values stay constant. In the provided solution, the part involving is evaluated by observing constant values on subintervals, while the part involving is handled by symmetry through the substitution .
Using those exact observations from the solution leads to the final reported value . Hence the required numerical answer is .
Common mistakes
Assuming the greatest integer function can be removed before checking where or changes range is incorrect. The floor value is piecewise constant, so the interval must be split where the expression crosses integers.
Treating as an odd function without handling the floor operation carefully is incorrect. The floor of a negative number does not behave like the negative of the floor in general, so symmetry arguments must follow exactly from the given working.
Using the antiderivative of or directly is wrong here because the integrand contains and , not and themselves. First determine the integer values taken on each subinterval.
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