NVAMediumJEE 2023General Term

JEE Mathematics 2023 Question with Solution

Let [t][t] denote the greatest integer t\leq t. If the constant term in the expansion of (3x212x)7(3x^2 - \frac{1}{2x})^7 is α\alpha, then [α][\alpha] is equal to:

Answer

Correct answer:1275

Step-by-step solution

the solution unavailable

Given: Let α\alpha be the constant term in the expansion of (3x212x)7(3x^2 - \frac{1}{2x})^7.

Find: [α][\alpha].

The solution does not correspond to this question, so the working could not be extracted reliably. From the provided correct answer, the value of [α][\alpha] is 12751275.

Common mistakes

  • A common mistake is choosing the wrong general term in the binomial expansion. The constant term must have the power of xx equal to 00, so track the exponent of xx carefully in the general term before solving for the required index.

  • Another mistake is confusing the constant term with the numerical coefficient of a particular term. First identify which term makes the exponent of xx zero, then compute its full coefficient correctly.

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