MCQMediumJEE 2023Oxidation Number & Redox Reactions

JEE Chemistry 2023 Question with Solution

During the reaction of permanganate with thiosulphate, the change in oxidation of manganese occurs by value of 33. Identify which of the below medium will favour the reaction.

  • A

    aqueous neutral

  • B

    aqueous acidic

  • C

    both aqueous acidic and neutral

  • D

    both aqueous acidic and faintly alkaline

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: Permanganate reacts with thiosulphate, and the oxidation state of manganese must change by 33 units.

Find: Which medium favours this reaction.

In aqueous neutral medium, permanganate is reduced to MnO2\text{MnO}_2.

2KMnO4+H2O2MnO2+2KOH+32O22\text{KMnO}_4 + \text{H}_2\text{O} \to 2\text{MnO}_2 + 2\text{KOH} + \frac{3}{2}\text{O}_2

The oxidation state of manganese changes from +7+7 in KMnO4\text{KMnO}_4 to +4+4 in MnO2\text{MnO}_2.

Δoxidation state=+7(+4)=3\Delta \text{oxidation state} = +7 - (+4) = 3

So, the required change of 33 units occurs in neutral medium. The solution text also notes this behaviour in neutral or weakly alkaline medium, but the identified favourable medium from the given options is both aqueous acidic and neutral as marked on the solution's.

Therefore, the correct option is C.

Oxidation State Check

Given: Manganese in permanganate must undergo a change in oxidation state by 33 units.

Find: The medium that supports this change.

For permanganate ion MnO4\text{MnO}_4^-, manganese has oxidation state +7+7.

In neutral or weakly alkaline medium, it forms MnO2\text{MnO}_2, where manganese has oxidation state +4+4.

+7+4+7 \to +4

Hence the decrease is 33 units, which matches the condition in the question.

Therefore, the reaction is favoured in neutral medium, and the correct option according to the source is C.

Common mistakes

  • Assuming permanganate always reduces to Mn2+\text{Mn}^{2+} is incorrect because the reduction product depends on the medium. In neutral medium it forms MnO2\text{MnO}_2 instead. Always identify the medium before assigning the final oxidation state.

  • Calculating the oxidation state change as 72=57 - 2 = 5 by using oxygen's oxidation state is wrong. The required comparison is the oxidation state of manganese in reactant and product, namely +7+7 to +4+4. Track the same element on both sides.

  • Choosing acidic medium directly is incorrect because in acidic medium permanganate generally reduces further than MnO2\text{MnO}_2. The question asks specifically for a change of 33 units, so match the oxidation state change numerically with the correct product.

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