Group–13 elements react with O2 in amorphous form to form oxides… — Solution | JEE Chemistry

MCQEasyJEE 2023Group 13 Elements

Group–13 elements react with $O_2$ in amorphous form to form oxides of type $M_2O_3$ ( $M$ = element). Which among the following is the most basic oxide?

(1) $Al_2O_3$

(2) $Tl_2O_3$

(3) $Ga_2O_3$

(4) $B_2O_3$

A
$Al_2O_3$
B
$Tl_2O_3$
C
$Ga_2O_3$
D
$B_2O_3$

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: Group–13 oxides $B_2O_3$ , $Al_2O_3$ , $Ga_2O_3$ , and $Tl_2O_3$ are to be compared.

Find: The most basic oxide among the given options.

As we move down Group 13, the metallic character increases, and hence the electropositive character increases. As electropositivity increases, the basicity of the oxides increases.

The order of basicity for Group 13 oxides is

B_2O_3 < Al_2O_3 < Ga_2O_3 < In_2O_3 < Tl_2O_3

Therefore, $Tl_2O_3$ is the most basic oxide. The correct option is B.

Common mistakes

Assuming that all Group–13 oxides have similar acid-base character is incorrect because basicity changes down the group with increasing metallic character. Compare their position in the group before choosing the oxide.
Choosing $Al_2O_3$ because it is a commonly discussed oxide is incorrect. $Al_2O_3$ is amphoteric, whereas oxides lower in the group become more basic due to greater electropositivity.
Confusing acidic nature of $B_2O_3$ with basicity trend is incorrect. $B_2O_3$ is the least basic among these, so the trend must be read from top to bottom in Group 13.

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Answer

Step-by-step solution

Common mistakes

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