MCQMediumJEE Main 2023 · 6 April, Shift 2Simple Harmonic Motion (SHM)

Physics Question from JEE Main 2023 · 6 April, Shift 2

A small particle of mass mm moves in such a way that its potential energy U=12mω2r2U = \frac{1}{2}m\omega^2 r^2 where ω\omega is constant and rr is the distance of the particle from origin. Assuming Bohr's quantization of momentum and circular orbit, the radius of the nnth orbit will be proportional to:

  • A

    nn

  • B

    n2n^2

  • C

    1n\frac{1}{n}

  • D

    n\sqrt{n}

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