A capacitor of capacitance 150.0 μ F is connected to an alternati… | JEE Main 2023 Physics PYQ

MCQEasyJEE Main 2023 · 6 April, Shift 2Alternating Current Basics

A capacitor of capacitance $150.0 \, \mu \text{F}$ is connected to an alternating source of emf given by $E = 36 \sin (120 \pi t)$ $\text{V}$ . The maximum value of current in the circuit is approximately equal to:

A
$\sqrt{2}$ $\text{A}$
B
$2\sqrt{2}$ $\text{A}$
C
$\frac{1}{\sqrt{2}}$ $\text{A}$
D
$2$ $\text{A}$

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