MCQEasyJEE 2023Characteristics of EM Waves

JEE Physics 2023 Question with Solution

The energy density associated with electric field EE and magnetic field BB of an electromagnetic wave in free space is given by ϵ0\epsilon_0 - permittivity of free space, μ0\mu_0 - permeability of free space:

  • A

    UE=ϵ0E22,  UB=B22μ0U_E = \frac{\epsilon_0 E^2}{2},\; U_B = \frac{B^2}{2\mu_0}

  • B

    UE=E22ϵ0,  UB=μ0B22U_E = \frac{E^2}{2 \epsilon_0},\; U_B = \frac{\mu_0 B^2}{2}

  • C

    UE=E22ϵ0,  UB=B22μ0U_E = \frac{E^2}{2 \epsilon_0},\; U_B = \frac{B^2}{2\mu_0}

  • D

    UE=ϵ0E22,  UB=μ0B22U_E = \epsilon_0 \frac{E^2}{2},\; U_B = \mu_0 \frac{B^2}{2}

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: The question asks for the energy density expressions associated with the electric field EE and magnetic field BB of an electromagnetic wave in free space.

Find: The correct expressions for UEU_E and UBU_B.

By theory of electromagnetic waves:

UE=12ϵ0E2U_E = \frac{1}{2}\epsilon_0 E^2

and

UB=B22μ0U_B = \frac{B^2}{2\mu_0}

Thus, the electric field energy density is proportional to ϵ0E2\epsilon_0 E^2 and the magnetic field energy density is proportional to B2μ0\frac{B^2}{\mu_0}.

Therefore, the correct option is A.

Quick Recall

Given: An electromagnetic wave in free space.

Find: Which option matches the standard energy density formulas.

Quick Tip: For electromagnetic waves, the energy is shared equally between the electric and magnetic fields. The standard expressions are:

UE=12ϵ0E2,UB=B22μ0U_E = \frac{1}{2}\epsilon_0 E^2, \qquad U_B = \frac{B^2}{2\mu_0}

Matching these directly with the options gives A.

Therefore, the correct option is A.

Common mistakes

  • Using UB=12μ0B2U_B = \frac{1}{2}\mu_0 B^2 is incorrect because magnetic energy density in free space is B22μ0\frac{B^2}{2\mu_0}, not proportional to μ0B2\mu_0 B^2. Always recall the standard form carefully.

  • Writing UE=E22ϵ0U_E = \frac{E^2}{2\epsilon_0} is incorrect because the electric energy density in vacuum is directly proportional to ϵ0\epsilon_0. Use UE=12ϵ0E2U_E = \frac{1}{2}\epsilon_0 E^2.

  • Assuming both expressions must contain the same parameter in the numerator is a conceptual error. The electric part involves ϵ0\epsilon_0, while the magnetic part involves μ0\mu_0 in the denominator. Memorize each formula separately.

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