MCQEasyJEE 2023Electromagnetic Spectrum & Applications

JEE Physics 2023 Question with Solution

For an amplitude modulated wave, the minimum amplitude is 3V3 \, \text{V}, while the modulation index is 60%60\%. The maximum amplitude of the modulated wave is:

  • A

    10V10 \, \text{V}

  • B

    12V12 \, \text{V}

  • C

    15V15 \, \text{V}

  • D

    5V5 \, \text{V}

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: modulation index m=0.6m = 0.6 and minimum amplitude Amin=3VA_{\min} = 3 \, \text{V}.

Find: maximum amplitude AmaxA_{\max} of the amplitude modulated wave.

For an amplitude modulated wave,

Amax=Ac(1+m),Amin=Ac(1m)A_{\max} = A_c(1+m), \qquad A_{\min} = A_c(1-m)

Using the given minimum amplitude,

3=Ac(10.6)=0.4Ac3 = A_c(1-0.6) = 0.4A_c

So,

Ac=30.4=7.5VA_c = \frac{3}{0.4} = 7.5 \, \text{V}

Now,

Amax=7.5(1+0.6)=7.5×1.6=12VA_{\max} = 7.5(1+0.6) = 7.5 \times 1.6 = 12 \, \text{V}

Therefore, the maximum amplitude of the modulated wave is 12V12 \, \text{V}. The correct option is B.

Common mistakes

  • Using Amin=AcA_{\min} = A_c is incorrect because the minimum envelope amplitude in amplitude modulation is Ac(1m)A_c(1-m). Always include the modulation index while relating minimum or maximum amplitude to the carrier amplitude.

  • Taking 60%60\% as 6060 instead of 0.60.6 gives a completely wrong result. Convert percentage modulation index to decimal before substitution.

  • Matching the final value with the marked answer without checking the calculation is incorrect. The solution contains inconsistent intermediate steps, so the amplitude-modulation relations must be applied carefully to verify the correct option.

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