JEE Chemistry 2023 Question with Solution

Given: The species are Xe$F_4$, S$F_4$, Si$F_4$, Br$F_4^-$, [Cu(N$H_3$)$_4$]$^{2+}$, [FeCl$_4$]$^{2-}$, and [PtCl$_4$]$^{2-}$.

Find: The number of species having square planar shape.

Use VSEPR theory for molecular species and standard coordination geometry for complexes.

• Xe$F_4$: square planar, type $AX_4E_2$
• S$F_4$: seesaw, not square planar
• Si$F_4$: tetrahedral, not square planar
• Br$F_4^-$: square planar, type $AX_4E_2$
• [Cu(N$H_3$)$_4$]$^{2+}$: square planar
• [FeCl$_4$]$^{2-}$: tetrahedral, not square planar
• [PtCl$_4$]$^{2-}$: square planar

Therefore, the square planar species are Xe$F_4$, Br$F_4^-$, [Cu(N$H_3$)$_4$]$^{2+}$, and [PtCl$_4$]$^{2-}$.

Hence, the number of such species is $4$.

The solution discusses a different question about square pyramidal species such as P$F_5$, I$F_5$, Br$F_5$, and XeO$F_4$. That list does not match the given question.

Since the question asks about square planar species among Xe$F_4$, S$F_4$, Si$F_4$, Br$F_4^-$, [Cu(N$H_3$)$_4$]$^{2+}$, [FeCl$_4$]$^{2-}$, and [PtCl$_4$]$^{2-}$, the correct evaluation must be based on the question text and the correct answer field.

Thus, the valid count is $4$.