Chemistry Question from JEE Main 2023 · 6 April, Shift 1

The equilibrium composition for the reaction $\text{PCl}_3 + \text{Cl}_2 \rightleftharpoons \text{PCl}_5$ at $298 \, \text{K}$ is given below:

$[\text{PCl}_3]_{eq} = 0.2 \, \text{mol L}^{-1}$, $[\text{Cl}_2]_{eq} = 0.1 \, \text{mol L}^{-1}$, $[\text{PCl}_5]_{eq} = 0.40 \, \text{mol L}^{-1}$ If $0.2 \, \text{mol}$ of $\text{Cl}_2$ is added, the equilibrium concentration of $\text{PCl}_5$ is $\times 10^{-2} \, \text{mol L}^{-1}$.