NVAMediumJEE 2023Amines (Classification & Properties)

JEE Chemistry 2023 Question with Solution

Number of isomeric aromatic amines with molecular formula C8H11N\mathrm{C_8H_{11}N}, which can be synthesized by Gabriel phthalimide synthesis is:

Answer

Correct answer:6

Step-by-step solution

Standard Method

Given: The molecular formula is C8H11N\mathrm{C_8H_{11}N} and the compounds must be aromatic amines obtainable by Gabriel phthalimide synthesis.

Find: The number of isomeric aromatic amines possible.

Gabriel phthalimide synthesis is used to prepare primary amines, that is, compounds of the form RNH2\mathrm{R-NH_2}. Therefore, we must count only those isomeric primary aromatic amines having formula C8H11N\mathrm{C_8H_{11}N}.

The degree of unsaturation is:

DU=C+1HN2=8+11112=95=4\mathrm{DU = C + 1 - \frac{H - N}{2} = 8 + 1 - \frac{11 - 1}{2} = 9 - 5 = 4}

A degree of unsaturation of 4\mathrm{4} indicates the presence of a benzene ring.

After accounting for the benzene ring, the remaining composition corresponds to a total of two carbon atoms outside the ring framework. Since the product must be a primary amine, the nitrogen must appear as NH2\mathrm{-NH_2} in the allowed structures.

Five aromatic amine structures are shown as possible ring-substituted isomers with benzene ring and NH2 group placements, illustrating counted isomer patterns for formula C8H11N.

The listed ring-substituted dimethylaniline representations must be counted with symmetry taken into account. As stated in the solution, some apparently different dimethylanilines are actually identical by symmetry, so they are not counted separately.

Therefore, the total number of possible isomeric aromatic amines that can be synthesized by Gabriel phthalimide synthesis is 66.

Count Using Unsaturation and Primary Amine Condition

Given: Molecular formula C8H11N\mathrm{C_8H_{11}N}.

Find: How many isomeric aromatic primary amines satisfy this formula and can be prepared by Gabriel phthalimide synthesis.

First use the unsaturation count:

DU=C+1HN2\mathrm{DU = C + 1 - \frac{H - N}{2}}

Substituting the values:

DU=8+11112=4\mathrm{DU = 8 + 1 - \frac{11 - 1}{2} = 4}

A value of DU=4\mathrm{DU = 4} is consistent with one benzene ring. Hence the compounds are aromatic and contain a benzene nucleus.

Now apply the condition from Gabriel phthalimide synthesis: it gives primary amines. So structures in which nitrogen is not present as NH2\mathrm{-NH_2} are excluded.

The valid isomers then include the possible aromatic primary amines with the required carbon count, including benzylamine-type and ring-substituted aniline-type arrangements, while equivalent substitution patterns are identified and merged.

Hence, after eliminating equivalent structures produced by ring symmetry, the final count is 66.

Common mistakes

  • Counting all aromatic amines with formula C8H11N\mathrm{C_8H_{11}N} without checking whether they are primary amines. This is wrong because Gabriel phthalimide synthesis prepares only primary amines. Only structures containing NH2\mathrm{-NH_2} should be included.

  • Ignoring symmetry in dimethyl-substituted aniline structures. This leads to overcounting because some substitution patterns that appear different on drawing are actually identical on the benzene ring. Always check ring equivalence before counting separate isomers.

  • Using the degree of unsaturation formula incorrectly. A wrong unsaturation count can lead to missing the benzene ring entirely. Compute DU=C+1HN2\mathrm{DU = C + 1 - \frac{H - N}{2}} carefully before proposing structures.

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