MCQMediumJEE Main 2023 · 6 April, Shift 1Uniform Circular Motion

Physics Question from JEE Main 2023 · 6 April, Shift 1

A particle is moving with constant speed in a circular path. When the particle turns by an angle of 9090^\circ, the ratio of instantaneous velocity to its average velocity is π:x2\pi : x\sqrt{2}. The value of xx will be:

  • A

    77

  • B

    22

  • C

    11

  • D

    55

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