MCQEasyJEE Main 2023 · 6 April, Shift 1Combinations (C(n,r))

Mathematics Question from JEE Main 2023 · 6 April, Shift 1

If 2nC3nC3=101\frac{^{2n}C_{3}}{^{n}C_{3}} = \frac{10}{1}, then the ratio (n2+3n):(n23n+4)(n^{2} + 3n) : (n^{2} - 3n + 4) is:

  • A

    27:1127:11

  • B

    35:1635:16

  • C

    2:12:1

  • D

    65:3765:37

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