MCQMediumJEE Main 2023 · 6 April, Shift 1Algebra of Matrices

Mathematics Question from JEE Main 2023 · 6 April, Shift 1

Let A=[aij]2×2A = [a_{ij}]_{2\times 2}, where aij0a_{ij} \ne 0 for all i,ji, j, and A2=IA^2 = I. Let aa be the sum of all diagonal elements of AA and b=Ab = |A|. Then 3a2+4b23a^2 + 4b^2 is equal to:

  • A

    1414

  • B

    44

  • C

    33

  • D

    77

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