MCQMediumJEE Main 2023 · 6 April, Shift 1Integration Techniques (Substitution, Parts, Partial Fractions)

Mathematics Question from JEE Main 2023 · 6 April, Shift 1

Let I(x)=x2(xsec2x+tanx)(xtanx+1)2dxI(x) = \int \frac{x^2(x\sec^2 x + \tan x)}{(x\tan x + 1)^2} \, dx. If I(0)=0I(0) = 0, then I(π4)I\left(\frac{\pi}{4}\right) is equal to:

  • A

    loge((π+4)216)+π24(π+4)\log_e\left(\frac{(\pi+4)^2}{16}\right) + \frac{\pi^2}{4(\pi+4)}

  • B

    loge((π+4)232)π24(π+4)\log_e\left(\frac{(\pi+4)^2}{32}\right) - \frac{\pi^2}{4(\pi+4)}

  • C

    loge((π+4)216)π24(π+4)\log_e\left(\frac{(\pi+4)^2}{16}\right) - \frac{\pi^2}{4(\pi+4)}

  • D

    loge((π+4)232)+π24(π+4)\log_e\left(\frac{(\pi+4)^2}{32}\right) + \frac{\pi^2}{4(\pi+4)}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Integration Techniques (Substitution, Parts, Partial Fractions) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions