JEE Chemistry 2023 Question with Solution

Given: Comparison of O-O bond length in $\text{H}_2\text{O}_2$ and $\text{F}_2\text{O}_2$, and comparison of O-H bond length in $\text{H}_2\text{O}_2$ with O-F bond length in $\text{F}_2\text{O}_2$.

Find: The correct values of $X$ and $Y$.

From the solution:

1. For the O-O bond, the explanation states that in $\text{F}_2\text{O}_2$, fluorine pulls electron density more strongly, and the conclusion given is that the O-O bond length in $\text{H}_2\text{O}_2$ is longer than in $\text{F}_2\text{O}_2$. Hence, $X = \text{longer}$.

2. For the second comparison, the solution explicitly concludes that the O-H bond length in $\text{H}_2\text{O}_2$ is shorter than the O-F bond length in $\text{F}_2\text{O}_2$. Hence, $Y = \text{shorter}$.

Therefore, the pair is $X = \text{longer}$ and $Y = \text{shorter}$.

This corresponds to option D as listed in the options.

Discrepancy note: the solution says "The Correct Option is C", but the written conclusion immediately below states "This corresponds to option (4)", which matches option D in the given list. The detailed conclusion is more consistent with the worked explanation, so the correct answer is taken as D.