MCQEasyJEE 2023Projectile Motion

JEE Physics 2023 Question with Solution

For a body projected at an angle with the horizontal from the ground, choose the correct statement.

  • A

    Gravitational potential energy is maximum at the highest point.

  • B

    The horizontal component of velocity is zero at the highest point.

  • C

    The vertical component of momentum is maximum at the highest point.

  • D

    The kinetic energy (K.E.) is zero at the highest point of projectile motion.

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: A body is projected at an angle with the horizontal from the ground.

Find: The correct statement about the projectile at its highest point.

At the highest point of projectile motion, the vertical component of velocity becomes

vy=0v_y = 0

while the horizontal component remains constant:

vx=ucosθv_x = u\cos\theta

So the horizontal velocity is not zero.

The gravitational potential energy is

U=mghU = mgh

and since the height is maximum at the highest point, gravitational potential energy is maximum there.

The vertical component of momentum is

py=mvy=0p_y = mv_y = 0

so it is not maximum.

The kinetic energy is

KE=12mv2KE = \frac{1}{2}mv^2

At the highest point, although

vy=0v_y = 0

we still have

vx=ucosθ0v_x = u\cos\theta \neq 0

Therefore, the speed is not zero, so kinetic energy is not zero.

The solution concludes with option D, but its own working states that gravitational potential energy is maximum at the highest point and that kinetic energy is not zero. Hence the working supports option A.

Therefore, the correct option is A.

Consistency Check with Extracted Solution

Given: Statements about velocity, momentum, potential energy, and kinetic energy at the highest point of a projectile.

Find: Which statement matches projectile motion facts.

From the extracted working:

  1. vy=0v_y = 0 at the highest point.
  2. vx=ucosθv_x = u\cos\theta remains constant.
  3. Ug=mghU_g = mgh is maximum when height is maximum.
  4. Kinetic energy is minimum, but not zero.

These observations eliminate:

  • Option B, because horizontal velocity does not become zero.
  • Option C, because vertical momentum is zero, not maximum.
  • Option D, because kinetic energy is not zero.

Thus only option A is consistent with the derivation shown in the solution, even though the page labels the option as D.

Therefore, the correct option is A.

Common mistakes

  • Assuming that the entire velocity becomes zero at the highest point is incorrect. Only the vertical component becomes zero; the horizontal component remains constant. Use vy=0v_y = 0 and vx=ucosθv_x = u\cos\theta separately.

  • Confusing minimum kinetic energy with zero kinetic energy leads to the wrong choice. At the highest point, speed is reduced but not zero because horizontal motion continues.

  • Treating vertical momentum as maximum at the highest point is wrong because momentum depends on velocity. Since vy=0v_y = 0 there, the vertical component of momentum is also zero.

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