Let α x = exp(x^β y^γ) be the solution of the differential equati… | JEE Main 2023 Mathematics PYQ

MCQMediumJEE Main 2023 · 1 February, Shift 2Linear Differential Equations

Let $\alpha x = \exp(x^\beta y^\gamma)$ be the solution of the differential equation $2x^2 y \, dy - (1 - xy^2) \, dx = 0$ , $x > 0$ , $y(2) = \sqrt{\ln_e 2}$ . Then $\alpha + \beta - \gamma$ equals:

A
$1$
B
$-1$
C
$0$
D
$3$

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