MCQMediumJEE Main 2023 · 1 February, Shift 2Linear Differential Equations

Mathematics Question from JEE Main 2023 · 1 February, Shift 2

Let αx=exp⁡(xβyγ)\alpha x = \exp(x^\beta y^\gamma) be the solution of the differential equation 2x2y dy−(1−xy2) dx=02x^2 y \, dy - (1 - xy^2) \, dx = 0, x>0x > 0, y(2)=ln⁡e2y(2) = \sqrt{\ln_e 2}. Then α+β−γ\alpha + \beta - \gamma equals:

  • A

    11

  • B

    −1-1

  • C

    00

  • D

    33

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