NVAMediumJEE 2023Definite Integrals

JEE Mathematics 2023 Question with Solution

If 01(x21+x4+x7)(2x14+3x7+6)1/7dx=17(11)m/n\int_{0}^{1} (x^{21} + x^4 + x^7)(2x^{14} + 3x^7 + 6)^{1/7} \, dx = \frac{1}{7} (11)^{m/n} where l,m,nNl, m, n \in \mathbb{N}, and m,nm, n are coprime, then l+m+nl + m + n is equal to:

Answer

Correct answer:63

Step-by-step solution

Standard Method

Given:

I=01(x20+x13+x6)(2x21+3x14+6x7)1/7dxI = \int_{0}^{1} (x^{20} + x^{13} + x^6)(2x^{21} + 3x^{14} + 6x^7)^{1/7} \, dx

Find: l+m+nl + m + n when the integral is written in the required form.

Use the substitution

t=2x21+3x14+6x7t = 2x^{21} + 3x^{14} + 6x^7

Then

dt=42(x20+x13+x6)dxdt = 42(x^{20} + x^{13} + x^6) \, dx

So the integral becomes

I=142011t1/7dtI = \frac{1}{42} \int_{0}^{11} t^{1/7} \, dt

because when x=0x = 0, t=0t = 0 and when x=1x = 1, t=11t = 11.

Now integrate:

I=142[t8/78/7]011I = \frac{1}{42} \left[ \frac{t^{8/7}}{8/7} \right]_{0}^{11} =14278(118/70)= \frac{1}{42} \cdot \frac{7}{8} \left(11^{8/7} - 0\right) =148(11)8/7= \frac{1}{48} (11)^{8/7}

Comparing with the required form, the solution gives

l=48,m=8,n=7l = 48, \quad m = 8, \quad n = 7

Hence

l+m+n=48+8+7=63l + m + n = 48 + 8 + 7 = 63

Therefore, the required answer is 6363.

Recognize the derivative pattern

Given: the integrand contains a polynomial factor multiplied by a power of another expression.

Find: how to convert it quickly into a direct substitution form.

Notice that

ddx(2x21+3x14+6x7)=42(x20+x13+x6)\frac{d}{dx}(2x^{21} + 3x^{14} + 6x^7) = 42(x^{20} + x^{13} + x^6)

So the polynomial factor is exactly proportional to the derivative of the inner bracket. This is why the substitution works immediately.

Therefore,

I=142011t1/7dt=148(11)8/7I = \frac{1}{42} \int_{0}^{11} t^{1/7} \, dt = \frac{1}{48}(11)^{8/7}

Thus the compared values are l=48l = 48, m=8m = 8, n=7n = 7, and hence l+m+n=63l + m + n = 63.

Common mistakes

  • Taking the wrong substitution. The useful substitution is the entire inner expression 2x21+3x14+6x72x^{21} + 3x^{14} + 6x^7 because its derivative produces the polynomial factor. Choosing only a part of it breaks the pattern.

  • Differentiating the inner expression incorrectly. ddx(2x21+3x14+6x7)=42(x20+x13+x6)\frac{d}{dx}(2x^{21} + 3x^{14} + 6x^7) = 42(x^{20} + x^{13} + x^6), not 42(x21+x4+x7)42(x^{21} + x^4 + x^7). Always match powers carefully.

  • Forgetting to change limits after substitution. Once tt is introduced, the limits must change from x=0,1x=0,1 to t=0,11t=0,11. Otherwise the transformed integral is inconsistent.

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