The area enclosed by the closed curve C given by the differential equation dy/dx + (x + a)/(y - 2) = 0, y(1) =…

Question

The area enclosed by the closed curve **C** given by the differential equation $$\frac{dy}{dx} + \frac{x + a}{y - 2} = 0, \quad y(1) = 0$$
is **$$4\pi$$**.
Let **P** and **Q** be the points of intersection of the curve **C** and the y-axis. If normals at **P** and **Q** on the curve **C** intersect the x-axis at points **R** and **S** respectively, then the length of the line segment **RS** is:

Accepted Answer

D. $$\frac{4\sqrt{3}}{3}$$

Answer

A. $$2\sqrt{3}$$

Answer

B. $$\frac{2\sqrt{3}}{3}$$

Answer

C. $$2$$

Answer & step-by-step solution

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