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MCQEasyJEE Main 2023 · 31 January, Shift 2Applications of Derivatives (Monotonicity, Extrema)

Mathematics Question from JEE Main 2023 · 31 January, Shift 2

The absolute minimum value of the function f(x)=∣x2−x+1∣+⌊x2−x+1⌋,where [t] denotes the greatest integer function, in the interval [−1,2], is:f(x) = |x^2 - x + 1| + \left\lfloor x^2 - x + 1 \right\rfloor, \quad \text{where} \, [t] \, \text{denotes the greatest integer function, in the interval} \, [-1, 2], \, \text{is:}

  • A

    34\frac{3}{4}

  • B

    32\frac{3}{2}

  • C

    14\frac{1}{4}

  • D

    54\frac{5}{4}

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