MCQMediumJEE Main 2023 · 31 January, Shift 2Functions

Mathematics Question from JEE Main 2023 · 31 January, Shift 2

Let f:R{2,6}Rf: \mathbb{R} \setminus \{ 2, 6 \} \to \mathbb{R} be the real-valued function defined as

f(x)=x2+2x+1x28x+12.f(x) = \frac{x^2 + 2x + 1}{x^2 - 8x + 12}.

Then the range of ff is:

  • A

    (,214][0,)\left( -\infty, \frac{-21}{4} \right] \cup [0, \infty)](streamdown:incomplete-link)

  • B

    (,214](0,)\left( -\infty, \frac{-21}{4} \right] \cup (0, \infty)

  • C

    (,214][214,)\left( -\infty, \frac{-21}{4} \right] \cup \left[ \frac{21}{4}, \infty \right)](streamdown:incomplete-link)

  • D

    (,214][1,)\left( -\infty, \frac{-21}{4} \right] \cup [1, \infty)](streamdown:incomplete-link)

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