MCQMediumJEE Main 2023 · 31 January, Shift 2Homogeneous Differential Equations

Mathematics Question from JEE Main 2023 · 31 January, Shift 2

Let y=y(x)y = y(x) be the solution of the differential equation

(3y25x2)ydx+2x(x2y2)dy=0,(3y^2 - 5x^2) y \, dx + 2x(x^2 - y^2) \, dy = 0,

such that y(1)=1y(1) = 1. Then

(y(2))312y(2)is equal to:\left( y(2) \right)^3 - 12y(2) \, \text{is equal to:}
  • A

    32232\sqrt{2}

  • B

    6464

  • C

    16216\sqrt{2}

  • D

    3232

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Homogeneous Differential Equations questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions