MCQMediumJEE 2023Argand Plane & Geometry

JEE Mathematics 2023 Question with Solution

For all zCz \in \mathbb{C} on the curve CC such that z=1|z| = 1, let the locus of the point z+1zz + \frac{1}{z} be the curve C1C_1. Then:

  • A

    the curves C1C_1 and C2C_2 intersect at 44 points

  • B

    the curves C1C_1 lies inside C2C_2

  • C

    the curves C1C_1 and C2C_2 intersect at 22 points

  • D

    the curves C2C_2 lies inside C1C_1

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: z=1|z| = 1 and the locus of z+1zz + \frac{1}{z} is called C1C_1.

Find: The correct relation between the curves C1C_1 and C2C_2.

From the solution, the working explicitly concludes:

z=eiθ    z+1z=eiθ+eiθ=2cosθz = e^{i\theta} \implies z + \frac{1}{z} = e^{i\theta} + e^{-i\theta} = 2\cos\theta

Hence the locus of z+1zz + \frac{1}{z} is a real line segment.

However, the provided the solution also contains a contradictory block mentioning

w=z+1z=4eiθ+14eiθw = z + \frac{1}{z} = 4e^{i\theta} + \frac{1}{4}e^{-i\theta}

which corresponds to z=4|z| = 4, not z=1|z| = 1. Despite this inconsistency, the solution explicitly states The Correct Option is B.

Therefore, using the solution, the correct option is B.

Detailed Note on the Inconsistency

Given: The question states z=1|z| = 1.

Find: Which option must be selected based on the provided source.

If we use the question statement directly, then let

z=eiθz = e^{i\theta}

so that

z+1z=eiθ+eiθ=2cosθz + \frac{1}{z} = e^{i\theta} + e^{-i\theta} = 2\cos\theta

Thus C1C_1 is the line segment on the real axis from 2-2 to 22.

But the options compare C1C_1 with C2C_2, and the definition of C2C_2 is missing from the question. Therefore the geometry cannot be completed from the question alone.

The source the solution is internally inconsistent: one part derives a result for z=4|z| = 4 and says the curves intersect at 44 points, while another part explicitly marks B as the correct option. Since the

Common mistakes

  • Using a solution step for z=4|z| = 4 when the question clearly states z=1|z| = 1. This mixes two different problems. Always verify that the modulus used in the working matches the given condition.

  • Assuming C2C_2 is known from context even though it is not defined in the extracted question. Without the definition of C2C_2, the comparison cannot be derived from the question text alone.

  • Forgetting that when z=1|z| = 1, we may write z=eiθz = e^{i\theta} and hence 1z=eiθ\frac{1}{z} = e^{-i\theta}. Missing this identity prevents the simplification of z+1zz + \frac{1}{z}.

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