JEE Chemistry 2023 Question with Solution

Given: Mass of organic compound = $0.492 \, \text{g}$, mass of $CO_2$ formed = $0.792 \, \text{g}$.

Find: Percentage of carbon in the organic compound.

First, calculate the mass of carbon present in $0.792 \, \text{g}$ of $CO_2$:

Now calculate the percentage of carbon in the compound:

Nearest integer:

Therefore, the percentage of carbon in the organic compound is $44$.

Given: On combustion, all carbon in the compound is converted into $CO_2$.

Find: Carbon percentage in the original sample.

In $CO_2$, the mass fraction of carbon is:

So the carbon obtained from $0.792 \, \text{g}$ of $CO_2$ is:

This $0.216 \, \text{g}$ carbon came from the original $0.492 \, \text{g}$ organic compound. Hence,

So the nearest integer value is $44$.