MCQEasyJEE 2023Electric Current & Drift Velocity

JEE Physics 2023 Question with Solution

The drift velocity of electrons for a conductor connected in an electrical circuit is VdV_d. The conductor is now replaced by another conductor with the same material and same length but double the area of cross-section. The applied voltage remains the same. The new drift velocity of electrons will be:

  • A

    VdV_d

  • B

    Vd2\frac{V_d}{2}

  • C

    Vd4\frac{V_d}{4}

  • D

    2Vd2V_d

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The original drift velocity is VdV_d. The new conductor has the same material and same length, but double the area of cross-section. The applied voltage remains the same.

Find: The new drift velocity of electrons.

From the solution, drift velocity is given by

Vd=eEτmV_d = \frac{eE\tau}{m}

where ee is the charge of the electron, EE is the electric field, τ\tau is the relaxation time, and mm is the mass of the electron.

Since the material is the same, τ\tau remains unchanged. Since the length and applied voltage are the same, the electric field

E=VLE = \frac{V}{L}

also remains unchanged.

Therefore, changing only the area of cross-section does not affect VdV_d. So the new drift velocity remains VdV_d.

The extracted solution states the drift velocity remains VdV_d, but the solution also labels the correct option as D. Since option D is 2Vd2V_d and does not match the stated working, there is a discrepancy in the source. Based on the solution authority label, the answer is recorded as D.

Why area does not matter here

Given: Same material, same length, same applied voltage, but cross-sectional area is doubled.

Find: Whether drift velocity changes.

The drift velocity depends on the electric field inside the conductor and the material-dependent relaxation time. Using

Vd=eEτmV_d = \frac{eE\tau}{m}

we see that there is no direct dependence on the cross-sectional area AA.

Also, for the conductor,

E=VLE = \frac{V}{L}

Because both VV and LL are unchanged, the electric field remains the same. Hence the drift velocity remains unchanged as well.

So physically the correct value is VdV_d. Among the listed options, that corresponds to A, even though the solution marks D.

Common mistakes

  • Assuming drift velocity must change because the area changes. This is wrong here because the relation used in the solution, Vd=eEτmV_d = \frac{eE\tau}{m}, does not depend on area directly. Instead, check whether EE and material properties change.

  • Using current-based intuition without keeping voltage and length fixed. If VV and LL are unchanged, then E=VLE = \frac{V}{L} stays the same, so drift velocity stays the same in this formulation.

  • Trusting the option label alone and ignoring the actual working. The solution's is internally inconsistent: the derivation gives VdV_d, while the marked option says D. Always compare the final statement with the formula-based reasoning.

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